2.3.4实例哈夫曼编码树
哈夫曼树用于给字符编码,其中哈夫曼树方法能够对于同样的信息谁用更少(或者说最少)的二进制位。其算法具体思想不作赘述,主要在于代码的实现
#lang sicp
;;首先思考如何表示树和叶
;;以下是叶子的表示
(define (make-leaf symbol weight);;构造一个叶子
(list 'leaf symbol weight)
)
(define (leaf? object);;判断是否是叶子
(eq? (car object)
'leaf))
(define (symbol-leaf leaf);;选择出叶子的符号集合
(cadr leaf)
)
(define (weight-leaf leaf);;选择出叶子的权重
(caddr leaf)
)
;;以下是树的表示
(define (append list1 list2);;这个方法用递归求两个节点符号集合的并集,下面要用
(if (null? list1)
list2
(cons (car list1) (append (cdr list1) list2))))
(define (make-code-tree left right);;构造一个编码树
(list left
right
(append (symbols left) (symbols right))
(+ (weight left) (weight right)))
)
(define (left-branch tree);;选择出左子树
(car tree))
(define (right-branch tree);;选择出右子树
(cadr tree))
(define (symbols tree);;选择出节点集合
(if (leaf? tree)
(symbol-leaf tree);;这里与书上不同
(caddr tree)))
(define (weight tree);;选择出节点权重
(if (leaf? tree)
(weight-leaf tree)
(cadddr tree)))
;;下面构造解码过程
(define (decode bits tree)
(define (decode-recur bits current-branch)
(if (null? bits)
'()
(let (
(next-branch (choose-branch (car bits) current-branch))
)
(if (leaf? next-branch)
(cons (symbol-leaf next-branch)
(decode-recur (cdr bits) tree))
(decode-recur (cdr bits) next-branch)))))
(decode-recur bits tree))
(define (choose-branch bit branch);;用来选择下一个分支
(cond ((= bit 0) (left-branch branch))
((= bit 1) (right-branch branch))
(else (error "bad bit"))
))
;;用来把一个节点加入集合;;默认序对是增序的
(define (adjoin-set x set)
(cond ((null? set) (list x))
((< (weight x) (weight (car set))) (cons x set))
(else (cons (car set (adjoin-set x (cdr set)))))))
(define (make-leaf-tree pairs);;构造一个叶子的初始排序集合。这里默认序对是增序的
(if (null? pairs)
'()
(let ((pair (car pairs)))
(adjoin-set (make-leaf (car pair)
(cadr pair))
(make-leaf-tree (cdr pairs))))))
(make-leaf-tree '((A 6)));;测试实例
2.3.4实例哈夫曼编码树
https://zzhygs.cn/index.php/archives/39/